A patient in a hospital is requested to have at least 84 units of drug A and 120 unites of drug B each day. Each gram of substance M contains 10 units of drug A and 8 units of drug B and each gram of substance N contains 2 units of A and 4 units of drug B. How many grams of substances M and N can be mixed to meet the minimum daily requirements?

Question

saifoo.khan · Answer

wait.. let me think.. @apam

saifoo.khan · Answer

M = A : B
      10 : 8

N = A : B 
       2 : 4

saifoo.khan · Answer

10x + 2y = 84,  
8x + 4y = 120

saifoo.khan · Answer

checking..

saifoo.khan · Answer

i think it's correct.

we will get 
M = 4 grams
N = 22 grams.

saifoo.khan · Answer

what do you think @PsychoTink

apoorvk · Answer

Right-o! @saifoo.khan

saifoo.khan · Answer

i can't believe i did that.

anonymous · Answer

I can:D

saifoo.khan · Answer

lol @Open2study

anonymous · Answer

I didn't solve the equations, I'm going to assume that works out, the final numbers work out properly though.

apoorvk · Answer

$$\large\mathfrak {\color{#CA4646 } {   LOL!!.}}$$

apoorvk · Answer

That was for @saifoo.khan and @Open2study .

anonymous · Answer

Wow @apoorvk , how did you do that lol?

apoorvk · Answer

$$\large\mathsf {\color{#CA9622}{You MeanLike--->}} \huge \mathfrak{\color{#56BBD9}{THIS?}}$$