Question

Identify the 42nd term of an arithmetic sequence where a1 = -12 and a27 = 66

Answer 1

let A_n = 66 so n= 27

66 = -12 + (27 -1)d
66 = -12 + (26d)
66 + 12 = 26d
78 = 26d
d = 3

so to find A_42

use A1 = -12
n = 42
d = 3

can you do that now?

Answer 2

Remember that\[a_{n} = a_{1} + (n-1)d\]where d is the common difference. Solve for d, and you will get 3. Then, use the same formula for n = 42:\[a_{42} = -12 + 41*3 = 111\]

Answer 3

Identify the 27th term of an arithmetic sequence where a1 = 38 and a17 = -74.

Answer 4

and thanks btw

Answer 5

Use the same formula and thought process again and you will be gold :-)

Answer 6

i got 96.5 :/ wat did i do wrong

Answer 7

Maybe you solved for d wrongly. Recheck it. I got d = 7 for the common difference.

Answer 8

A) -20.5
B) -151
C) -22.75
D) -144 those ar ethe possible choices

Answer 9

Oops, I got d = -7. So, we get:\[a_{27} = a_1 + 26*(-7) = -144\]

Answer 10

Identify the 35th term of an arithmetic sequence where a1 = -7 and a18 = 95 thanks