Question

Suppose while playing tennis, Venus gets her first serve in 75% of the time. when she gets her first serve in, she wins a point 80% of the time...

Answer 1

if she misses her first serve, her second serve goes in 90% of the time. whe this happens, she wins the point on her second serve 35% of the time.
find the probability that venus wins a point when she is serving.

Answer 2

probability was never my strong point, but I could take a guess at this.

Answer 3

you guys have any ideas of how to go about solving this?

Answer 4

\[p(wp)=p(wp|Gs1).P(Gs1)+p(wp|Gs2).P(Gs2)\]

Answer 5

what i would do would be:
\[.75*.80 + (1 - .75*.80)*.9*.35\]
the first part being the probability of her winning her first serve
and the second of her winning her second serve given a result of her first serve.

again its been forever since I've done any probability

Answer 6

p(wp|Gs1)=80% p(wp|Gs2)=35% p(Gs1)=75% P(Gs2)=90%

Answer 7

is the periods in between multiplications symbols? @RaphaelFilgueiras

Answer 8

tihs is the probability of win a point if she gets first server

Answer 9

a player is allowed two serves each time in tennis. sorry i forgot to mention that.

Answer 10

the secons time Gs2

Answer 11

P(wp) is the probability to win a pint

Answer 12

the question just says find the P when she is serving. it doesnt when wether is first or second. what shoudl i do?

Answer 13

that formula take accounting the two cases,its impossible she gain a ponit without serving

Answer 14

have you played tennis before?

Answer 15

or know how the serving works?

Answer 16

oh ok. the problem also says draw a tree diagram. i will post here.

Answer 17

nope.

Answer 18

in tennis you have two attempts to get in a good serve with each serve. IF you miss the first one you move onto the second.