What is the 35th term of the arithmetic sequence where a1 = 13 and a17 = -67?

Question

inkyvoyd · Answer

an=a1+d(n-1)

anonymous · Answer

given a1=13
and a17=-67
thus 16d=-67-13=-80
hence d=-5
a35 =a1+34d
=13+34(-5)
=13-170
=-157
is ithe answer -157

callisto · Answer

Same type of question as the previous one.
an = a1 + (n-1)d
a17 = 13 + (17-1)d
-67 = 13 + 16d
Solve d.
Then, apply the formula again
a35 = a1 + (35-1)d
      = 13 + 34 d.
You can solve it

campbell_st · Answer

use the formula to find d, the common difference

$$T _{n} = a + (n - 1) d$$   

you  have a = 13, n = 17 and T17 = -67

then when you have d... use the formula again with n = 35, a = 13

anonymous · Answer

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