Question

What is the 35th term of the arithmetic sequence where a1 = 13 and a17 = -67?

Answer 1

an=a1+d(n-1)

Answer 2

given a1=13
and a17=-67
thus 16d=-67-13=-80
hence d=-5
a35 =a1+34d
=13+34(-5)
=13-170
=-157
is ithe answer -157

Answer 3

Same type of question as the previous one.
an = a1 + (n-1)d
a17 = 13 + (17-1)d
-67 = 13 + 16d
Solve d.
Then, apply the formula again
a35 = a1 + (35-1)d
= 13 + 34 d.
You can solve it

Answer 4

use the formula to find d, the common difference

\[T _{n} = a + (n - 1) d\]

you have a = 13, n = 17 and T17 = -67

then when you have d... use the formula again with n = 35, a = 13