PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!

Question

anonymous · Answer

attachment

campbell_st · Answer

(1)  differentiate the curve  y = x^2....


(2) the derivative is the equation of the gradient of the tangent. 
     to find the gradient at x =2, substitute  x = 2 into the derivative

hopefully you'll find m = 4

anonymous · Answer

Oh thank you! What's about the mulpitle choice? I think the second one is the answer, isn't it?

campbell_st · Answer

thats correct, one point is (2, 4) and the 2nd point is unknown, but the line intersects twice

anonymous · Answer

mmm it says that's wrong((

anonymous · Answer

Use the point-slope form to define the line, then put it into the form the problem requires.

anonymous · Answer

Yes, Campbell helped to find the 1st part, but the seconf (multiple choice) was wrong. What do you think is the correct answer in multiple choice?

campbell_st · Answer

the equation of the line is y = 4x - 4

so the line isn't a tangent at (1, 1) its a tangent st (2, 4)

so the solution must be that it doesn't intersect the curve it only touches it at (2,4) as a tangent only has 1 point of contact

for me its a badly worded question

anonymous · Answer

The tangent line has slope four through the point (2,4) so using the point-slope form of the line....$$y-4=4(x-2)\implies y-4=4x-8\implies y=4x-4$$

anonymous · Answer

so the 3 rd answer is correct. Right?

campbell_st · Answer

for me its the 1st answer as the tangent on has 1 point of contact with the curve there is no intersection

anonymous · Answer

Wrong(((((((

anonymous · Answer

Eh....The line is tangent to the parabola, y = x2, at the point (1, 1) was correct

campbell_st · Answer

wow... that means y = x^2 and y = 4x - 4 are equal... find the point of contact

x^2 = 4x - 4

x^2 - 4x + 4 = 0   (x -2)^2 = 0

point of contact is 2

goes to show... maths can't answer everything