Question

As I don't know, I can only ask. - Photoelectric effect

Answer 1

you know the relation of frequency of EM radiations to energy??

Answer 2

E=hf
f=c/λ
=> E = h(c/λ) ?

Answer 3

yes ... exactly!!

Answer 4

E=hf
f = E/h

Answer 5

this one gives the frequency of the radiation ...
and don't forget to convert energy in to Joules <--since it is given in eV

Answer 6

http://www.askiitians.com/iit_jee-Atomic_Structure/Photoelectric_Effect

Answer 7

Oh....'pass' .... unit problem :S

Answer 8

don't you know it??

Answer 9

I think I should have known it...

Answer 10

you know the relation between potential and energy??
what would be the energy of election in 1V potential??

Answer 11

1eV = 1.602x10^-19 J

Answer 12

If I remember it correctly...

Answer 13

yes

Answer 14

yes ... use that to change 4.8 ev to joules, and divide it by plank constant to find the frequency.

Answer 15

Yup... I got it. I just discovered that I forgot to change the unit. Thank you.

Answer 16

well, I think you can do second and the third ...
I can tell the stopping potential would be 1.9 V <---3

Answer 17

I got ci, but not cii ...

Answer 18

???

Answer 19

Oh... I guess I've cut the question... sorry

Answer 20

the answer of b) and c) would be 1.9ev and 1.9V

Answer 21

ci and cii... I can't get cii ...

Answer 22

is that the plate??

Answer 23

The emitter, so i think so..

Answer 24

it will not have any change ... neither in velocity or energy of electrons or stopping potential.

it would only change current.

Answer 25

But the min. value for Vs is different, according to the answer in the book

Answer 26

I shouldn't be ... I think. just the intensity of the light is changed.

Answer 27

The intensity changes because the 'force applied' changes? (in the ball kicking case)

Answer 28

intensity would change !!!
since intensity is defined as Energy per unit area per unit time <--- higher frequency has higher energy
or to be exact: intensity is proportional to square of frueqency

Answer 29

I think I'll understand it. Thank you.

Answer 30

since in this case, frequency of the light is unchanged, .. only the energy of incident area is changed by sin(80) ... times, that would mean, electons would have same energy, but the amount of electrons will be less by sin(10) times the original.

Answer 31

BTW what is the answer???

Answer 32

1.84eV

Answer 33

Ahh ...that enerygy ... !!!! LOL

Answer 34

Sorry... 1.84V....

Answer 35

now I'm confused ... I'll reply later.

Answer 36

Thank you. Note that there are many problems with my book.

Answer 37

well, I trust this forum
http://www.physicsforums.com/showthread.php?t=486401
It says the same as me.
But still I cannot be sure

Answer 38

Thanks though!

Answer 39

you are welcome ... !!
although I only managed to confuse myself.

Answer 40

At least I learnt something from this question. Thank you so much!

Answer 41

@shayanreloaded Thank you so much! That website is very useful!!! I wish I could have known it earlier :(

Answer 42

@Callisto np better late than nvr eh?

Answer 43

Perhaps. Thanks again!

Answer 44

Here comes another version of the graph by different book