Question

19 gms of molten SnCl2 is electrolysed for sometime using inert electrodes until 0.119 gms of Sn is deposited at cathode. No substance lost during electrolysis. Find the ratio of Sncl2 : SnCl4

Answer 1

@mos1635 - can you help me out with this if you can?

Answer 2

1:2

Answer 3

noway :) its 71.34 : 1

Answer 4

but how do you do it? the way i did it was -
No. of moles of SnCl2 before reaction = 19/187.5 = 0.1001 moles;
No of moles of Sn discharged = 0.119/119 = 0.001 moles;
No of moles of Sn remaining in the solution = 0.1001 - 0.001 = 0.099 moles;
therefore, same no. of moles of Sncl4 will be produced.
therefore mass of Sncl4 produced = atomic mass x no.of moles = 261 x 0.099 = 25.8 gms.
therefore ratio = 19/25.8 = 0.73 :1 which is wrong

Answer 5

i can not get the reaction........
i suppose that prodused Cl oxidize part of SnCl2 to SnCl4.....is that wrigt??/

Answer 6

Sncl2 ----> Sn + SnCl4

Answer 7

2 Sncl2 ----> Sn + SnCl4
n1 0 0
-n2 +n2/2 +n2/2
n1-n2 n2/2 n2/2

Answer 8

please check moleculare masses

Answer 9

n1=19/187.5
n2/2=0.119/119 =>n2=0.002
asked ratio
(n1-n2)*187.5/(n2/2)*261
=71.36:1

Answer 10

that is an exact resalt with no entermidiate aproximations

Answer 11

i was thinking about that all night
in cases like this where so exact resalts are asked 71.34 : 1
we mast give the exact constants we are suppose to use
for example i use for Cl MM=35.5 sor Sn 119 there for my initial MM for SnCl was 120
in your case i have used your given values for MMs as you have posted above.