solve: y^4/=34
Is this your question \[y^4=34\] ???
y^4/5=34 sorry
We have \[\frac{y^4}{34}=5\] multiply both sides by 34, we get \[y^4=170\] as here the power of y is 4 so this equation will have 4 roots or zeros \[y^2= \pm(170)^{\frac{1}{2}}\] so \[\huge y= \pm (170)^{\frac{1}{4}}, \pm i (170)^{\frac{1}{4}}\] where i = \(\large \sqrt{-1}\)
Do you understand this?
Yes :) but i meant for the exponent to be the fraction 4/5, like y^(4/5)=34
Oh:(
Then we have \[y^{\frac{4}{5}}=34\] so, reverse the powers \[\huge y=34^{\frac{5}{4}}\]
Did you understand this?
Yep, is that the final answer?
Yeah, actually we had \[y^{\frac{4}{5}}=34\] Raise both sides to a power of 4/5 \[\large y^{\frac {4}{5} \times \frac{5}{4}}=34^{\frac{5}{4}}\] so we get \[y^1=34^{\frac{5}{4}}\] or \[\huge y=34^{\frac{5}{4}}\]
Do you get this?
yep thanks!
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