Question

represents the curve given by x = t ^ 2 - 2t, y = t find the area under the curve from t = 2 to t = 3

Answer 1

Hi Kevindorado
Do you know how to find the Area of a curve using Integration? An idea will be to diffentiate x wrt to t. Since the limits are expressed in t, its best to integrate with t. Are you able to take it from there?

Answer 2

Area = \[\int\limits_{2}^{3} y dx\]
y=t
x=t^2
dx = 2t dt
so,
Area = \[\int\limits_{2}^{3} (t)(2t) dt\]
= \[\int\limits_{2}^{3} 2t ^{2}\]
i think you can solve it from here onwards.

Answer 3

*dt