Question

Use transformations and zeros of the quadratic function f(x) =(x+2)(x-6) to determinate the zeros.

Answer 1

e) y=-f(x+1) and f) y=f(-x-2)

Answer 2

(e) y = -f(x+1) = -(x+3)(x-5) has zeros at x=-3 and x=5

Answer 3

(f) y = f(-x-2) = (-x)(-x-8) has zeros at x=0 and x=-8.

Answer 4

but how did you get that answer? the steps?

Answer 5

Well, for example, in (e) replace x with x+1 in the original expression for f(x), then make the whole thing negative.

Answer 6

whole thing negative? so it's going to be y= -f(x+1) -> y= (-x-1)?

Answer 7

No. When you replace x with x+1 you get (x+1+2)(x+1-6) = (x+3)(x-5). Making this negative, -(x+3)(x-5). See this in my first post?

Answer 8

ohhh, yes thank you!

Answer 9

welcome.