You draw 2 cards from a well-shuffled deck of 52 cards. After you draw the first card, you do not replace it in the deck. The probability of drawing the ace of spades on your first draw is 1/52. What is the probability of P(get queen of hearts on second draw | get ace of spades on first draw)?

Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms

Is the answer 1/2652

Question

You draw 2 cards from a well-shuffled deck of 52 cards. After you draw the first card, you do not replace it in the deck. The probability of drawing the ace of spades on your first draw is 1/52. What is the probability of P(get queen of hearts on second draw | get ace of spades on first draw)?

Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms

Is the answer 1/2652

anonymous · Answer

yes i think hte answer is 1/2652

anonymous · Answer

1/51

anonymous · Answer

how man just give the formula please i m also confused

anonymous · Answer

you know you have 51 cards left in the deck
you know there is still one queen of hearts because you know the first card was not the queen of hearts. 
so you know your probablity of getting a queen of hearts is now $\frac{1}{51}$

anonymous · Answer

there is no "formula' for these. most conditional probability questions you get the answer by thinking about what you know happened at the first try, not by a formula

anonymous · Answer

these problems confuse the crap out of me!!!

anonymous · Answer

yes of course they are confusing until you get used to them. but try only to think about what you know, rather than appealing to some sort of formula

anonymous · Answer

say you have 10 balls in an urn, 4 red, 6 blue
you pick one, see that it is red, and then without replacing pick another. what is the probablity the second one is also red?

no formula, you know there are now 9 balls in the urn of which 3 are red (because you picked a red one first) so your probabililty is $\frac{3}{9}$

no formula, just thinking