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Find the sum. 1 + 3 + 5 + ... + 1743 Express the sum using summation notation. 3 + 12 + 27 + . . . + 75
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\[Sn=(a1+an).n/2\] an=a1+(n-1).r
Can you find n from the formula?
yes put an as 1743
r is 2
this is an arithmetic series where you know the 1st and last terms and the common difference so find the number of terms by using \[T _{n} = a + ( n - 1) d\] 1743 = 1 + ( n - 1) 2 1743 = 2n - 1 1744 = 2n n = 872 to find the sum use \[s _{n}= n/2[ a + l]\] a = 1st term l = last term \[s _{872}=872/2[1 + 1744]\] \[s _{872}= 760384\]
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My S_872 = 764, 744
Oh, n = 877
oops \[s _{872}= 872/2[1+1743] = 760384\]
Campell's right! My manual calculation is off :(
lol... the problem we all have
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