Question

rt(3) tan 3θ + 1 = 0

Answer 1

\[\sqrt{3} \tan 3\theta +1 = 0\]

Answer 2

\[\tan 3\theta=\frac{-\sqrt{3}}{3}\]
\[3\theta=\frac{5 pi}{6},\frac{11 pi }{6}, \frac{17 pi}{6}, \frac{23pi}{6}, \frac{29pi}{6}, \frac{35pi}{6}\]
\[\theta=\frac{5pi}{18}, \frac{11pi}{18}, \frac{17pi}{18}, \frac{23pi}{18}, \frac{29pi}{18}, \frac{23pi}{18} + 2pin\]

Answer 3

Whoops. Forgot 35 pi/18

Answer 4

tg(3.θ)=−3√/3→3.θ=(K).pi−pi/6
k is interger

Answer 5

\[k pi/3+ pi/18\] is what i entered and its wrong? Any idea why?

Answer 6

-pi/18

Answer 7

see?

Answer 8

yepp thankss!