Mathematics
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OpenStudy (anonymous):
For the given cost function
C(x)=7550+700 x + 1.8 x^2 and the demand function p(x) = 2100.
Find the production level that will maximize profit.
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OpenStudy (anonymous):
but i dont no how to
OpenStudy (anonymous):
43303.0447
OpenStudy (anonymous):
i dont think thats right
OpenStudy (anonymous):
sorry
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
hey
OpenStudy (anonymous):
hey
OpenStudy (anonymous):
so r u a boy
OpenStudy (anonymous):
a girl
OpenStudy (anonymous):
???
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OpenStudy (anonymous):
i am despreat
OpenStudy (anonymous):
@rukh So what is Profit ?
OpenStudy (anonymous):
i dont know. this is all the problem says
OpenStudy (anonymous):
ho knows\\\\\\\\
OpenStudy (anonymous):
i suppose u have to find profit some how which i dont know
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OpenStudy (anonymous):
What is the relation between profit and Cost?
OpenStudy (anonymous):
well profit is equal to revenue minus cost
OpenStudy (anonymous):
Great, how do find Revenue?
OpenStudy (anonymous):
revenue is = P(which is demand)*x
OpenStudy (anonymous):
Excellent! Show me your R (x) equation :)
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OpenStudy (anonymous):
rx eq is 2100x
OpenStudy (anonymous):
Wow, then can you write Profit P(x) equation?
OpenStudy (anonymous):
yes it (7550+700x+1.8x^2)-(2100x)
OpenStudy (anonymous):
Actually P (x) = R (x) - C(x)
Simplify it, will you :)
OpenStudy (anonymous):
i got the solution its 388.889
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OpenStudy (anonymous):
thanks for the brainstorming
OpenStudy (anonymous):
Are you sure it's correct?
OpenStudy (anonymous):
yes it is...thanks for ur help