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Mathematics 7 Online
OpenStudy (anonymous):

For the given cost function C(x)=7550+700 x + 1.8 x^2 and the demand function p(x) = 2100. Find the production level that will maximize profit.

OpenStudy (anonymous):

but i dont no how to

OpenStudy (anonymous):

43303.0447

OpenStudy (anonymous):

i dont think thats right

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

hey

OpenStudy (anonymous):

hey

OpenStudy (anonymous):

so r u a boy

OpenStudy (anonymous):

a girl

OpenStudy (anonymous):

???

OpenStudy (anonymous):

i am despreat

OpenStudy (anonymous):

@rukh So what is Profit ?

OpenStudy (anonymous):

i dont know. this is all the problem says

OpenStudy (anonymous):

ho knows\\\\\\\\

OpenStudy (anonymous):

i suppose u have to find profit some how which i dont know

OpenStudy (anonymous):

What is the relation between profit and Cost?

OpenStudy (anonymous):

well profit is equal to revenue minus cost

OpenStudy (anonymous):

Great, how do find Revenue?

OpenStudy (anonymous):

revenue is = P(which is demand)*x

OpenStudy (anonymous):

Excellent! Show me your R (x) equation :)

OpenStudy (anonymous):

rx eq is 2100x

OpenStudy (anonymous):

Wow, then can you write Profit P(x) equation?

OpenStudy (anonymous):

yes it (7550+700x+1.8x^2)-(2100x)

OpenStudy (anonymous):

Actually P (x) = R (x) - C(x) Simplify it, will you :)

OpenStudy (anonymous):

i got the solution its 388.889

OpenStudy (anonymous):

thanks for the brainstorming

OpenStudy (anonymous):

Are you sure it's correct?

OpenStudy (anonymous):

yes it is...thanks for ur help

OpenStudy (anonymous):

think u can help with this one?? http://openstudy.com/study?signup#/updates/4f935981e4b000ae9ec9ffda

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