Question

find three consecutive odd integers such that the product of the first and the second exceeds the third by 8.

Answer 1

numbers are n,n+2, n+ 4 where n is odd
and
n(n+2) = n+4 + 8
n(n+2) = n + 12

solve this for n
can you do that?

Answer 2

n^2 + n - 12 = 0

Answer 3

this equation has 2 roots , one even and one odd
its the odd one u require

Answer 4

do you need help solving this equation?

Answer 5

lol yea im lost

Answer 6

you need 2 numbers which when multiplied give -12 and when added give 1

these are 4 and -3

so we get (n+4)(n-3) = 0
so
n = -4 or 3
n is given as odd so it must be 3

so your 3 consecutive odd numbers are 3, 5 and 7

Answer 7

oooooh thanx:)

Answer 8

yw