2570 g of water is heated at just boiling, if the water absorbs 4.97x 10^5 J of heat in the process, what is the initial temperature of the water? I need to know how to solve for the 'delta T' part. that is where I am hung up.

Question

2570 g of water is heated at just boiling, if the water absorbs 4.97x 10^5 J of heat in the process, what is the initial temperature of the water?     I need to know how to solve for the 'delta T' part. that is where I am hung up.

experimentx · Answer

head absorbed  =  masss in kg * sp. heat capacity * difference in temperature

Final temperature will be 373 K
so initial temp will be 373 - difference in temp K

p0sitr0n · Answer

E = mcdelta T