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Mathematics 13 Online
OpenStudy (anonymous):

Filling in the scale factor chart.

OpenStudy (anonymous):

OpenStudy (anonymous):

Number 11.

OpenStudy (p0sitr0n):

its easy. the factor is k^2 when its are and k^3 when its volume. dividing areas will give 0.111(1/9) =k^2. so k = 1/3

OpenStudy (anonymous):

Yeah, but since it's area, don't I have to square it?

OpenStudy (p0sitr0n):

so the volume is 12 * k^3 = 12* 1/27 = 12/27 = 4/9

OpenStudy (p0sitr0n):

no, they ask you for k, not for k^2. you find it by dividing the areas. after, square root

OpenStudy (anonymous):

For the volume, I got 5748, by cubing 1/9. is it right? @P0sitr0n

OpenStudy (p0sitr0n):

when u cube 1/9, u get \[1^3/3^3=1/27\] remember, your k is the relation between your sides. K^2 is the area relation, and volume is k^3. So, to find k, u have to area1/area2 = k^2 , sqrt(k) when u find it, remember to check in which dimension u are. 1 dimension is side = k^1 2 dimension is area = k^2 (like cm^2) 3 dimension is volume =k^3 (like cm^3)

OpenStudy (anonymous):

How does 1/9=1/27?

OpenStudy (p0sitr0n):

look. your k = 1/3. you CAN NOT pass from are to volume, as you can not pass from k^2 to k^3 1/9 is k^2, so all you have to do is \[\sqrt{1/9}\] this is your k = 1/3 now you get it in ^3, so (1/3)^3 is 1/27

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