Question

See attachment for question.

Answer 1

I get 2058 for the area of triangle ABC.

Answer 2

finding the other side. (120 - 18*2 )/2= 42.
perimeters ratio = side ratio = 120/91

Answer 3

It asks for the area ratio @P0sitr0n

Answer 4

wait, which question is that?

Answer 5

if so, k^2 = 1.74

Answer 6

What do you mean??

Answer 7

i dont see where it asks for the area ratio.

Answer 8

It isn't 2058?

Answer 9

it asks for side lenghts raito

Answer 10

Oh! Gosh, I put up the wrong question. I'm sorry!

Answer 11

hmm

Answer 12

its ok :)

Answer 13

This is the correct one @P0sitr0n

Answer 14

ok
so
\[b*h/2 =A\]
\[7*h/2 = 42\]
so we solve and h = 12
Now we find k between sides
h1/h2 = 42/12 = 3.5
area is k^2, so 3.5^2 = 12.25

Answer 15

@P0sitr0n But couldn't I do another way?

Answer 16

And it also says to find the area ratio, so isn't it 1:49?

Answer 17

hmm. u mean not by passing from k^2 to k to k^3?
Sure. ((k^2)1/2)3
this gives k^3/2
type on calculator k^3/2 and you will get from k^2 to k^3

Answer 18

Wait, where did k^3 come from??? I get a kind of confused when you keep mentioning k^3or2

Answer 19

Isn't it just 1:49?

Answer 20

k is need to be between ONLY the same sides. Per axample, if u take a height, u need to take another height. So, height 1/height 2 = 42/12 =3.5^2 = 12.25
so k^2 is 12.25
area is 42 * 12.25 = 514.5

Answer 21

I don't get that for the area, I keep getting 2050

Answer 22

well, lets make it clear.
k is a ratio between something. sides , per example.
so, if we put sides in ^2, to get the area, we must ^2 their ratio too.
same with volume (^3)

Answer 23

the area 1 must be smaller than area 2. thats good. next, you miltiply your area by your ratio k^3. This way, 12.25 * 42 = 514.5.

Answer 24

I still don't get it /:

Answer 25

Isn't this a 2D figure? Why did you bring up the volume?

Answer 26

hmmmm. i think its pretty simple.
the volume is only to show u in general. u can forget it for this quesiton, but it may occure in other.

Answer 27

I can't, it's my homework

Answer 28

k = 1 dimension = side/side = k^1
k^2 = 2 dimensions = area/area

Answer 29

did you listen to the teacher?
i think he is better than me for saying all that.

Answer 30

Find the height of triangle DEF using the \(A = \frac{1}{2}bh\) formula and the given base length. Then you can compare the heights using a ratio. That would also be the ratio of perimeters as well because the figures are similar. Then, you can square the ratio to find the ratio of areas.

Answer 31

exact

Answer 32

@AccessDenied Could I also set up a proportion?

Answer 33

Hmm.. what proportion would you set up?

Answer 34

42/6=x/42

Answer 35

Then you square the 42/6 to find the area

Answer 36

I can tell that my way is wrong, but can you explain how?

Answer 37

Oh, you're comparing
\[ \frac{\text{area}}{\text{height}} => \frac{42}{6} = \frac{x}{42}\] ?

Answer 38

Yes

Answer 39

It'd work, but you just have the wrong height "6"
Since A = 1/2 b h:
42 = 1/2 (7) h
42 = 7/2 h
2/7 * 42 = h
12 = h

The x-value you find is the area of ABC, so you put that over 42, the area of DEF, to find the ratio.
x/42

Answer 40

147 for the area of ABC?

Answer 41

Yep

Answer 42

you can NOT compare area and sides, as you can not compare liters and grams, and Newtons and Pascals. COnvert to the same units

Answer 43

So it's 514.5?

Answer 44

514.5 and not 147?

Answer 45

my error.

Answer 46

So is the ratio 4:49?

Answer 47

147 is what i get from the ratio

147/42 = 7*7*3 / 7*2*3
= 7 / 2

It should be 49:4, since its from ABC to DEF

Answer 48

Oh right, yes. Thank you @P0sitr0n and @AccessDenied !

Answer 49

really sorry, im tired.

Answer 50

I wish they got rid of the one person best answer /:

Answer 51

Oh good! So it splits evenly :)

Answer 52

woah, glitched. D:
gave two best answer medals I think. o.o

Answer 53

Aha, no you just gave one to positron :P

Answer 54

I removed the one i gave to you (twice), but I think it did go through
I have the option to give another one now too. o.O

Answer 55

Hm, strange o_O

Answer 56

k, guess i should go mention this. :P