Question

A 0.280kg ball makes an elastic head on collision with a second ball initially at rest.The second ball moves off with half the original speed of the first ball. what is the mass of a second ball? what fraction of the original kinetic energy gets transfered to the second ball.?

Answer 1

m1*V=M1*V1+M2*V2 (conservation of momentum)
M1*(V-V1)=M2*V2 (1)

1/2*M1*V^2=1/2*M1*V1^2 + 1/2*M2*V2^2
M1(V^2-V1^2)=M2*V2^2
M1*(V-V1)*(V+V1)=M2*V2^2 divide with (1)
V+V1=V2 but V2=V/2 so V1=-V/2
aplay that to (1)
M1*3V/2=M2*V/2
m2=3m1

Answer 2

thank you