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Mathematics 13 Online
OpenStudy (anonymous):

Hey...how do you use the mean value theorem in calculus?

OpenStudy (anonymous):

example? it is used in different ways

OpenStudy (anonymous):

it is used for example to find the bound of a function at a point it is also used to prove the fundamental theorem of calculus

OpenStudy (anonymous):

a basic example? that would explain the idea

OpenStudy (anonymous):

so you have a specific problem? i can make one up if you like

OpenStudy (anonymous):

no specific problem

OpenStudy (anonymous):

usually they come in one or two ways: the silly ones that say for example: find the number \(c\) in the interval \([1,3]\) guarenteed to exist by the mvt for the funciton \[f(x)=x^2-6x+6\] your job is to write \[f'(x)=2x-6\] \[f(3)=-3\] \[f(1)=1\] \[\frac{f(b)-f(a)}{b-a}=\frac{-3-1}{3-1}=-2\]and then solve \[2c-6=-2\] for c to get \[c=2\]

OpenStudy (anonymous):

how is f(1)=1

OpenStudy (anonymous):

or they come like this: suppose \(f(1)=5\) and \(f'(x)<1\) for all x what is the biggest \(f(4)\) can be ? i just made that example up. for the function i made up \(f(x)=x^2-6x+6\) we have \(f(1)=1-6+6=1\)

OpenStudy (anonymous):

you can make up a different one, and if you want a better understanding, convince yourself that the "c" that must exist by the mean value theorem is always in the center of the interval if your function is a quadratic (like the one i made up)

OpenStudy (anonymous):

You can use it to show \[ |\sin(x)-\sin(y)| \le |x-y| \] for all x and y. In general if you have a function such that \[|f'(x)|\le K \] for all x then \[| f(x) -f(y) | \le K |x-y| \] for all x and y

OpenStudy (anonymous):

eliassaab wrote an example like the second one i wrote, since we know that the derivative of sine is cosine and therfore can never be bigger than 1 this is probably a homework problem in your text

OpenStudy (anonymous):

ohhh i get it! thank u so much!

OpenStudy (anonymous):

yw

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