Question

y=cosx*cotx
find y'

Answer 1

-sinx(cosx/sinx) +{-sinx(sinx)+cosx(cosx)}/sin^2x (cosx)?

Answer 2

y'=cosx*(-(cosec ^2 x) + cotx * (-sinx)
y'=-[(cosx*cosec^2 x)+ cotx*sinx]

Answer 3

cotx = cosx /sinx
y = cos x * cos x/ sin x
y = cos²x s/sin x
y' = 1 + tan x * sin x + cos² x * cos x / sin² x

Answer 4

if you know diff of cot x why complicate?????

Answer 5

i still dont get it, mind showing the steps?

Answer 6

do you know the product rule of differentiation in calculus...???

Answer 7

yes.

Answer 8

apply it here....simple...

Answer 9

the derivative i get is.

Answer 10

cosx - cosx/sin^2x