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logx+log(x/10)+log(1/19)=1 all are to base 9 solve
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x=sqrt190
thanks for the DETAILED explanation
Since log a + log b = log (a*b) and log a to base a = 1
sorry sqrt 190 is wrong
correct one is sqrt190*9
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sorry for not giving detailed solution.
method: log ( x * x/10 * 1/19)= log 9. x^2/190=9 x=sqrt(190*9)
Sorry for miscalculation earlier. I wad half asleep
*was
to solve the eqn we have to eliminate log. u can write 1=log9(base is 9) and use loga + logb=loga*b.on simplifying u get logxsquared/109=log9 and u get the answer
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