a baseball player hits a baseball into the air with an initial veri]tical velocity of 48 feet per second from a height of 3 feet.
write an equation that gives the baseballs height as a function of the time in seconds after it is hit.
after how many seconds doesthe baseball reach its maximum height?
what is the maximum height?

PLEASE HELP

Question

a baseball player hits a baseball into the air with an initial veri]tical velocity of 48 feet per second from a height of 3 feet.
write an equation that gives the baseballs height as a function of the time in seconds after it is hit.
after how many seconds doesthe baseball reach its maximum height?
what is the maximum height?

PLEASE HELP

anonymous · Answer

h(t) = ut - 16t^2 + 3
in your case h(t) = 48t - 16t^2 + 3

anonymous · Answer

you can find time when height is a maximum by differentiating - have you studied calculus?

anonymous · Answer

no i havent - algebra:)

anonymous · Answer

velocity at time t = 48  - 32t
at maximum height velocity = 0
so 0 = 48 - 32t
 t = 1.5 seconds at maxm height

anonymous · Answer

now to find the maximum height you plug in t = 1,5 
in h(t) = 48t - 16t^2 + 3
can you continue with that?

anonymous · Answer

thnx so much-yes

anonymous · Answer

you're very welcome