Question

Did I expand it wrong?
y= (1+cos^2 (x))^6
y' = 6 ( 1+cos^2 (x) )^5 (2) (cosx) (-sinx)

Answer 1

Hi cmkc109 :)

No I don't think so. It seems right buddy..

Answer 2

But then the answer given is -6 sin 2x (1+cos^2 (x))^5

Answer 3

sin(2x)?? double angle?

Answer 4

OK let me try..

Answer 5

it doesnt have the bracket..but i assume it is the same

-6 sin 2x (1+cos^2 x)^5

Answer 6

since 2sinxcosx = sin2x

Answer 7

That's all you do to simply further!

Answer 8

ohh..that rule, thanks both of you :)

Answer 9

\[\large y=(1+\cos^2x)^6\]\[\large y'=6(1+\cos^2x)^5\frac{d}{dx}(1+\cos^2x)\]\[\large y'=6(1+cos^2x)^5(2cosx)(-sinx)\]\[\large y'=-6(1+cos^2x)^5(2sinxcosx)\]\[\large y'=-6(1+cos^2x)^5(sin2x)\]

Answer 10

thanks both!