Question

just a little indices query...



*please wait whilst i write it as an equation*
Thanks =)

Answer 1

express \[16^{3}\]
as \[2^{?}\]

Answer 2

or express
\[125^{4/3}\]
as \[5^{?}\]

Answer 3

first one is (2^4)=16

so replace 16 with 2^4-->(2^4)^3--->2^12=4096, which is the the same value as 16^3

Answer 4

for the second one, i will only give you a hint: 125=5^3

Answer 5

sly hint... ahaha =)

Answer 6

how about expressing\[1/27\] as \[3^{?}\]
?

Answer 7

So, yes that was sly hint. Whaddya think? Try a guess! ;p

Answer 8

125 \[125^{4/3} = (5^{3})^{4/3} = 5^{4}\]

Answer 9

hmm, do you know that,

\[\large x^{-m} = \frac {1}{x^m} \]

Answer 10

1/27 = 3^(-3)

Answer 11

thaanksss =)

Answer 12

Are you getting how we do this, the concept? Try to understand what LagrangeSon and Zeerak did up there^^.

Answer 13

yeahh thanks but i got an advanced one that im trying now... its hardd :/

Answer 14

Hmm, post that one too just in case you want to verify your answer :)

Answer 15

work out\[(1/64)^{-1/2}\]

Answer 16

It is 8.

Answer 17

howww?? :S

Answer 18

\[1/64^{-1/2} = 64^{1/2} = 8^{2*1/2} = 8\]

Answer 19

ahh i seee! thanks =)

Answer 20

:)