Find the derivative of
y= (1+sinx) / (1-sin2x)

Question

Find the derivative of 
y= (1+sinx) / (1-sin2x)

anonymous · Answer

dont know what i 've did wrong... i'm close to the answer..

shayaan_mustafa · Answer

HI cmkc109 :)
first we have to use quotient rule. did you use that?

anonymous · Answer

yes. I used that

anonymous · Answer

answer given is cosx- cosxsin2x + 2cos2x + 2sinx cos  / (1-sin2x)^2

but i only got cosx- cosxsin2x + 2cos2x   / (1-sin2x)^2

anonymous · Answer

http://www.wolframalpha.com/input/?i=derivative+(sin(x)+%2B+1)%2F(1+-+sin(2+x))&t=sftb01 Click on "Show steps"

anonymous · Answer

different ans than my ans key has.. i guess the one u have simplifies more..dont really get it lol.. never know u can find derivative in wolframalpha

anonymous · Answer

$$\frac{\cos (x)}{1-\sin (2 x)}+\frac{2 (\sin (x)+1) \cos (2 x)}{(1-\sin (2 x))^2} $$simplified is:$$\frac{-2 \sin ^3(x)+\cos (x)+2 \cos (2 x)}{(\sin (2 x)-1)^2} $$