\[\LARGE \log(\log x)+\log(\log x^5-4)=0\] A) x=1 B) x=-1 C) x=-2 D) x=0
let log x = u
... let me see what I can do. :)
but then ... \[\LARGE \log(u)+\log(5u-4)=0\] \[\LARGE \log(5u^2-4u)=0\] now according to: \[\LARGE \log_ab=c \quad \Longrightarrow b=a^c\] I thought about: \[\LARGE 5u^2-4u=10^0\] \[\LARGE 5u^2-4u-1=0\] \[\LARGE u_{1/2}=\frac{4\pm\sqrt{16-20\cdot (-1)}}{10}\] \[\LARGE u_{1/2}=\frac{4\pm6}{10}\] \[\LARGE u_1=1 \quad \quad ,\quad \quad u_2=-\frac25\] so... \[\LARGE \log x=1 \Longrightarrow x=10\] and \[\LARGE \log x=-\frac25 \Longrightarrow x=\frac{1}{\sqrt[5]{100}}\] ... O_O
sorry.. it's -1/5 \[\LARGE x=\frac{1}{\sqrt[5]{10}}\]
@satellite73 since you love logs :P , please can you have a look what I'm doing wrong :(
why it says "e" to me ! ?:O http://www.wolframalpha.com/input/?i=+log%28log+x%29%2Blog%28log+x%5E5-4%29%3D0
use this log[10, x]
but it says there that is in base 10 !... it doesn't matter, I don't know if my PC went crazy, but your link doesn't show a solution or something. O_O , :( ..@experimentX :)
your method is right .. I think so.
but my options... :(
put this on wolfram alpha. solve log[10, log [10, x]] + log[10, (log[10, x^5] - 4)]
x=10 ? :O
No.
then how... can you provide a better solution, that's what I'm looking for.
@Mertsj
Wolf says 2.80688
So based on the posted problem and the posted answers, I'd say there is an error in the posting.
Make sure when you type it into wolf that you use the base 10 option.
ok hold on a second...
Question Nr. 7
Well, just try replacing x with each of those answers. Which one works?
Every single one of them results in a negative argument in log(x^5-4)
I don't know :( I'm pretty lost \[\LARGE \log_{10}(0)=?\] since: \[\LARGE \log_ab \quad\quad \quad ,\quad \quad b>0\] so I guess it can't be option D :O
10^0=1 but 10 ^x cannot be 0
log 0 is undefined.
I see this is in a foreign language. Perhaps the notation means something different. Why do you need to do this problem anyway?
just to exercise , nothing special ^_^ ... It's ok, I'll ask my professor probably there's a mistake in the book. ;) Thanks for the help @Mertsj @experimentX
yw
yw When you find out, you might enlighten us as well.
lol , ok. Although I'm sure there must be a mistake ;) . Have a nice day .
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