Question

y=e^e^x
find y'

Answer 1

y' = u' e^u
= e^x * e^(e^x)

Answer 2

xe^ex?

Answer 3

NO

Answer 4

can u go through the steps? i dont get it.

Answer 5

The formula:
y' = u' e^u

Answer 6

u = e^ --> u' = ??

Answer 7

Then just plug it into the formula :)

Answer 8

i dont get it..

Answer 9

mind going thru the steps?

Answer 10

In differentiating a function that contains another function (or a series of functions for some), you apply the chain rule. Actually, you perform the chain rule when you differentiate and differentiate the different layers of functions until you reach a point when you are differentiating the most basic function x and you just get 1.

To get the y' of e^e^x, we should note that the first layer is e^x where x here is e^x. The deriv of e^x = e^x, so the deriv of the first layer is e^x, but since x here is e^x, we make it e^(e^x). Now for the second layer, it's just e^x where x here is still x. So the deriv of the second layer is e^x where x is x. Now for the third layer, the function is just x, and its deriv is just 1. This is where we stop.

Deriv of first layer: e^(e^x)
Deriv of second layer: e^x
Derive of third layer: 1 (stopped here)

Then we just multiply everything, as this is what the chain rule states. So the derivative of the e^(e^x) = (e^(e^x))(e^x)(1) or simply (e^(e^x))(e^x).

Answer 11

where did u get the second layer as e^x as?

Answer 12

Because usually it is just e^x, right? That's the most basic form of that function. In this case, however, e was raised to another e^x, which is another function in itself. That's the second layer.

Answer 13

then what is the first layer?

Answer 14

The first layer is e^(e^x) as a whole. The second layer is the e^x inside the first layer (the power).

Answer 15

oh ok

Answer 16

Is it clear already? :)

Answer 17

somewhat...