Question

y = –x^2 – 6x – 5 , find the zeros of the functions w/steps please.

Answer 1

To find the zeroes of the function,

1. Set y = 0:
y = -x^2-6x-5
0 = -x^2-6x-5

2. factor a value common to each term. In this case -1 is the common factor:
0 = -1(x^2 + 6x + 5)

3. Divide both sides by -1
0 = x^2 + 6x + 5

4. Factor as usual by finding two numbers that multply to get 5, yet add to get 6:
The two numbers are 5 and 1. Use those two numbers to split the middle term then continue factoring:

0 = x^2 + 5x + 1x + 5
0 = x(x+5)+1(x+5)
0 = (x+5)(x+1)

5. Use the zero product property:

x + 5 = 0
x + 1 = 0

Thus the two zeroes are x = -1,-5

Answer 2

Got it. Thanks Hero!

Answer 3

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