Question

SolutionS of x^2+12x+10=0

Answer 1

-1 and -11

Answer 2

How do you get -1 and -11?

Answer 3

Is it right?

Answer 4

No, since x=-1 and x=-11 being solutions =>x+1=0 and x+11=0
(x+1)(x+11) = x^2 + 11x + x + 11 = x^2 + 12x + 11, not x^2 + 12x + 10

Answer 5

I don't know then

Answer 6

The discriminant is 104, which is not a perfect square and thus indicates that there are two solutions that are irrational. I'll use quadratic formula since I already have the discriminant:
\[ x = \frac{-b \pm \sqrt{D}}{2a} \]

\[ x=\frac{-12 \pm \sqrt{104}}{2(1)}\\
= \frac{-12 \pm \sqrt{4\times26}}{2}\\
= \frac{-\cancel{12}6 \pm \cancel2\sqrt{26}}{\cancel2}\\
x= -6 \pm \sqrt{26} \]

Answer 7

That's what I got but I just take the real number

Answer 8

I see now, though it would be more accurate to use \(x=-6 \pm \sqrt{26}\) than approximating to nearest integer :)

Answer 9

yea ok

Answer 10

my bad