how do you do (3)/(2x)-(1)/(2(x+6))=1 ?

Question

p0sitr0n · Answer

you need to have a common number in order to add both fractions. 
when done the steps, it gives
$$(x+9)/x(x+6)=1$$
you cross multiply, and move all to one side (left)
after, you solve the quadratic equation using formula

p0sitr0n · Answer

so, from here we get $$x+9 = x(x+6)$$
$$x+9 - x^2-6x =0$$
use this formula to find roots
$$x1,x2 = (-b \pm \sqrt{b^2-4ac})/2a$$
where a is the term before x^2
where b is term  (coefficient) of x
and c is without x
so we get a = -1 b=-5 c=9
if theres 2 roots = 2 points of intersection of the parabola with the line y=1
1 root = only 1
negative number under root = no intersection , no solution

p0sitr0n · Answer

-x^2 -5x +9 =0