Question

how do you do (3)/(2x)-(1)/(2(x+6))=1 ?

Answer 1

you need to have a common number in order to add both fractions.
when done the steps, it gives
\[(x+9)/x(x+6)=1\]
you cross multiply, and move all to one side (left)
after, you solve the quadratic equation using formula

Answer 2

so, from here we get \[x+9 = x(x+6)\]
\[x+9 - x^2-6x =0\]
use this formula to find roots
\[x1,x2 = (-b \pm \sqrt{b^2-4ac})/2a\]
where a is the term before x^2
where b is term (coefficient) of x
and c is without x
so we get a = -1 b=-5 c=9
if theres 2 roots = 2 points of intersection of the parabola with the line y=1
1 root = only 1
negative number under root = no intersection , no solution

Answer 3

-x^2 -5x +9 =0