Question

4sin2x-1 = 1 find all possible solutions in degrees and radians from 0 - 2pi

Answer 1

Is it sin 2x or sin^2 x?

Answer 2

4 sin (2x) -1 = 1

Answer 3

:)

Answer 4

4sin2x-1=1
4sin2x=2
sin2x=2/4
sin2x=1/2

solve from there

Answer 5

there are four solutions?!?

Answer 6

those are the steps

Answer 7

sorry i would rather do it the way my eacher taught me. so i hade sin 2x = 1/2. now what?

Answer 8

the answers are pi/6, 11pi/6, 5pi/6

Answer 9

if i plug in sin 1/2 into my calculator i get 30 degrees then divide by 2 to get 15 degrees as reference angle?

Answer 10

\[\sin(2x)=\frac{1}{2}\]\[2x=\frac{pi}{6}, \frac{5pi}{6}, \frac{13pi}{6}, \frac{17pi}{6}\]
\[x=\frac{pi}{12}, \frac{5pi}{12}, \frac{13pi}{12}, \frac{17pi}{12}\]

Answer 11

ugh guys shouldn't there only be 2 solutions because sin is positive so it must be in quadrant 1 and 2!!!!

Answer 12

you don't understand this has confused me for months and my teacher doesn't care

Answer 13

yes sorry my mistake pi/6 and 5pi/6 are your answers

Answer 14

No. Since the argument is 2x that means you have to make two complete revolutions. You will be dividing by 2 so to get all the answers between 0 and 2 pi after dividing by 2, you have to start out with all the answers between 0 and 4 pi

Answer 15

@Brent0423 Are you sure the information you are disseminating is correct?

Answer 16

it says between 0-2pi

Answer 17

All 4 of those answers are between 0 and 2 pi

Answer 18

omg im so screwed

Answer 19

Why?

Answer 20

i really don't get this. its supposed to have 2 solutions

Answer 21

Who said?

Answer 22

because sin is positive

Answer 23

so Q1 Q2

Answer 24

Plug those 4 answers I gave you into your calculator and see if they make the original equation true.

Answer 25

how..?

Answer 26

wait wouldn't it be 15 degree not 30?