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16^-n =8^2n simplify
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add a "log" at each side and solve
\[(2^4)^(-n) = (2^3)^(2n)\] \[2^(-4n) = 2^(6n)\]
ok so what would the answer be
16^-n = 64^n 1/16^n = 64^n n = 0, i suppose for you
thank you so much!! i got it!!
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