sin(x+2pi/3)+sin(x-2pi/3)=-rad2/2
Solve for 0 lessthanorequalto x less than 2pi

Question

sin(x+2pi/3)+sin(x-2pi/3)=-rad2/2
Solve for 0 lessthanorequalto x less than 2pi

anonymous · Answer

$$\sin(x +2pi/3 ) + \sin(x - 2pi/3) = \sqrt{2}/2$$

anonymous · Answer

$$Solve for 0 \le x < 2pi$$

anonymous · Answer

hint, rewrite the above as $-\sin(x)$ and then solve

anonymous · Answer

$$= - \sqrt{2}/2$$

anonymous · Answer

thats what it equals i wrote it wrong

anonymous · Answer

did you solve for x?

anonymous · Answer

no i mean i wrote the original equation wrong and didnt place a negative in front

anonymous · Answer

ok so you have 
$$-\sin(x)=-\frac{\sqrt{2}}{2}$$
$$\sin(x)=\frac{\sqrt{2}}{2}$$ solve for x

anonymous · Answer

two solutions would be $x=\frac{\pi}{4}$ and $x=\frac{3\pi}{4}$

anonymous · Answer

noo i dont have that.... i have - sinx + sin 2pi/3 -sinx + sin 2pi/3 = rad2/2

anonymous · Answer

what do i do from there?

anonymous · Answer

I have 2sinx = -rad2/2    what do i do now?

anonymous · Answer

Can you help?

anonymous · Answer

welli have to solve for in radians

anonymous · Answer

0 <or equal x < 2pi

hero · Answer

satellite should come back here and post a more complete explanation. I keep telling reminding him not to half-arse his explanations.

anonymous · Answer

im not friends with him, so i cant make him come back

hero · Answer

He's offline and most likely done for the night.

anonymous · Answer

are you paid to do this?

hero · Answer

I get paid the same amount as you do.

anonymous · Answer

i dont get apid for this ohhh so you dont haha

hero · Answer

I can get the proper solution to this for you

hero · Answer

I am useful in that regard.

anonymous · Answer

?

anonymous · Answer

bye

hero · Answer

Where are you going?