Question

solve the equation

log base 4 (x^2-3x)=1

Answer 1

\[1 = \log_{4} 4\]

Answer 2

but how did you get that answer?

Answer 3

you can transform the right side into logarithms\[\log_{4} \left( x^2 - 3x \right) = \log_{4} 4\]and then you get\[\left( x^2 - 3x \right) = 4\]

Answer 4

x^2-3x = 4
Can you continue?