Question

the distribution of body weights has a mean of 188 pounds and a standard deviation of 7. If 267 men belong to the gym, how many of them do you expect to be over 200 pounds?

Answer 1

Since 188 lbs is mean of 267 men in the gym,
z = (200 - 188 ) / 7 = 1.714
P ( x > 200 ) = P ( z > 1.714 )

Answer 2

AH! THANK YOU!

Answer 3

wait here are the answers they give to chose from
About 12 or 13 men
B

About 10 or 11 men
C

About 11 or 12 men
D

About 255 or 256 men

Answer 4

You need the table to look up Z score!

Answer 5

Hold on!

Answer 6

okay!

Answer 7

still with me?

Answer 8

I can't find the table, you probably has it in your book appendix!

Answer 9

I'm not sure how to use the table..

Answer 10

Match the row has number "1" with the column .71

Answer 11

.9591

Answer 12

i think..

Answer 13

wait thats wrong

Answer 14

.9649

Answer 15

Are you sure?

Answer 16

pretty sure..

Answer 17

i went to the 1.7 row, then the .01 column...that's what my z table had

Answer 18

So now you know how to use it, right?

Answer 19

well, idk what i'm supposed to do with tha number, to get one of the answers i gave you above..

Answer 20

Multiply .9649 * 267 = 257 men

Answer 21

ooo! i was trying to do it to 188 men. lol

Answer 22

About that number!

Answer 23

thanks for the help!

Answer 24

I just don't have the table to match up, but I trust you read it right!

Answer 25

i'm about to post another question