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Express answer in exact form. A segment of a circle has a 120 arc and a chord of 8in. Find the area of the segment.
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what are the units for that 120 arc?
Oh sorry! 120 degrees, and 8 sqrt 3 inches. My bad!
So you have a circle with center 0, and a chord from point P to point Q on the circle, measuring m inches. PQ0 is a triangle with angle 120 degrees, if you draw a line splitting it in half, you have a 90 degree angle, a 60 degree angle, and a length m/2 inches. For this we see the equation, r*sin(theta) = m/2, or more specifically, r * sin(60) = m/2. From here you should be able to compute the area.
|dw:1335152554946:dw| (8sqrt3)^2=r^2 + r^2 -2(r)(r)cos120 r^2 can be found area can be calculated by (r^2) pi (120/360)
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