Question

Integrate please?
(2r-1) cos sqrt[3(2r-1)^2 +6] / sqrt[3(2r-1)^2 +6]

Answer 1

\[(2r-1) \cos \sqrt{3(2r-1)^{2}+ 6} / \sqrt{3(2r-1)^{2}+ 6}\]

Answer 2

I think substituting the angel would be a nice start.

Answer 3

3(2r-1)^2 +6 = t^2

Answer 4

meaning?

Answer 5

Integration by Substitution?

Answer 6

yes, what ive got my final answer is 1/12 sin sqrt[3(2r-1)^2 +6]
but its wrong :(

Answer 7

\[(2r-1)\frac{\cos t}{t} \cdot\frac{2t}{12(2r-1)} dt\]
\[\frac16\cdot \sin t\]

Answer 8

or, 1/6 sin sqrt[3(2r-1)^2 +6]