if a cylindrical barrel measures 22 inches in diameter, how many inches will it roll in 8 revolutions along a smooth surface?

Question

anonymous · Answer

Well, how many inches do you think it will roll in 1 revolution?

anonymous · Answer

4 inches?

anonymous · Answer

Draw a picture, draw more than one.  This about what is rolling.  Think about what is making contact with the ground.  A small hint, the circumference is somehow involved.  Bedtime now.  good luck

anonymous · Answer

In one revolution the barrel will roll a distance of Pi*22 inches the length of a circle's circumference.
In eight revolutions 8*Pi*22 = 552.93 feet.

anonymous · Answer

The circumference of the cylindric barrel will tell us how many inches it rolls in 1 revolution.
The circumference of a circle is Πd. Since the diameter is 22:
$$Π d * 22$$
This equals.. 22/7 x 22 = 69.14 inches per revolution.
For 8 revolutions, multiply by 8.
$$69.14 \times 8 = 553.12$$
The cylindrical barrel travels 553.12 inches in 8 revolutions.