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Given that x+y= 0 is tangent to y=F(x), find F(x) if F'(x) = x
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how do u find the antiderivative of y?
Have you taken up the Fundamental Theorem of Calculus?
integrate to find F(x) \[\int\limits x dx\] use the tangent properties to evaluate the constant
yes i have
\[F(x) = \frac{1}{2}x^{2} +\frac{1}{2}\]
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how did you get this answer? Can someone explain step by step?
\[F(x) = \int\limits_{}^{}x = \frac{1}{2}x^{2} +C\] F'(x) = slope of tangent line = -1 --> x = -1 x+y =0 -1 + y = 0 y = 1 so plug in the point and solve for C 1 = 1/2*(-1)^2 +C
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