This is not a riddle! well kinda riddlish >:)) how to integrate \(\LARGE \int{}{} \frac{1}{\cos x} dx\) step-by-step
I was gonna say Weierstrass substitution but meh, too long.
idk :'( I can use integration by parts but @Mimi_x3 has a better way to do it.
@Mimi_x3 is a calculus expert huh
Turn 1/cos(x) to sec(x) and multiply both numerator and denominator by sec(x)+tan(x).
Yeah, that's what Mimi does. The blockcoder way.
then \(\LARGE \frac{\sec^{2} x + secxtanx}{secxtanx}\)
what does that mean o.O
let u = secx tanx ??
There's a missing + in the denominator. =))
\[\int secx \frac {secx+tanx}{secx+tanx} dx\]\[=\int \frac {sec^x+secxtanx}{secx+tanx} dx\]\[=\int \frac {1}{secx+tanx} d(secx+tanx)\] =ln |secx + tanx| +C
where'd that second to the last line come from again?
\[\frac{d}{dx} (secx + tanx) = sec^2x + secxtanx\]
oh i see
so it was let u = secx + tanx right...
Perhaps... It should be... I don't know... I just did it in this way. Sorry!!!
i like u substitution :P hmm..so this doesnt have the trig substitution yet...gotta find one
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