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Simplify the following product of complex numbers. (8 + i) · (-4 – 3i)
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-32-24i-4i-3i^2 -32-28i+3 -29-28i
(8 + i) · (-4 – 3i) =8(-4) + (-3i)(8)+(i)(-4)+(i)(-3i) =-32-24i-4i+3 =-29-28i
but i^2=-1 so the answer is -29-(-28)=-1
no, there is only one i in -29-28i (-1)=i^2 -29-28i=-29+28(i^2)(i) but not -29-(-28)=-1
sorry
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thanks. yall make this look to simple been out of school for years im more of a statistics guy.
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