Question

Simplify the following quotient of complex numbers into the form a + bi.

-9+2i/-8-9i

Answer 1

-9+2i/-8-9i
=(-9+2i)(-8+9i) / (-8-9i)(-8+9i) <---multiply both numberator and denomintor with the conjugate of denominator so as to remove i in denomintator

=(-9+2i)(-8+9i)/ (64+81)
=(72-97i-18) / 145
=54/145 -(97/145)i

Answer 2

thanks again. so u have to take the i from the denominator