Questions about Limits, please HELP someone.
\[\lim_{x \rightarrow 0} x / 2 (1-\sqrt{x+1)}\]
Clarify the question please. Is it \[(x/2)(1-\sqrt{x+1)}\] or \[x/(2(1-\sqrt{x+1})\]
the second one. im not sure of how to do the fraction over thingy hee
Ans is ±1
Solution Applying L'hopital rule: Differentiating both numerator and denominator: \[\lim_{x \rightarrow 0} 1/2(0-1/2\sqrt{x+1})\] simplifying this we get, \[\lim_{x \rightarrow 0}-\sqrt{x+1}\] Now substitue 0 instead of x, you will get your answer
okay thank you. can i know, is there any way we can do by using the conjugate method?
sure Posting now
\[\lim_{x \rightarrow 0} x/2(1-\sqrt{x+1}) * (1+\sqrt{x+1})/(1+\sqrt{x+1})\] \[\lim_{x \rightarrow 0} x*(1+\sqrt{x+1})/2(1-x-1)\] \[\lim_{x \rightarrow 0} 1+\sqrt{x+1}/2\] Now Substitute x=0 and get your answer :)
In The last step I forgot the brackets. \[\lim_{x \rightarrow 0} (1+\sqrt{x+1})/2\] Should make it more clear now
okay thank you so much :)
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