use stoichiometry to calculate the number of moles produced of Iron (lll) oxide given three moles of water 1 mole Fe 1 mole Fe2O3 3 moles H2O 3 moles Fe2O3
the number of gram equivalents of all the species in a reaction are the same. no. of gram equivalents = given mass/equivalent mass.now equivalent mass=molecular mass/n factor. so no. of gram equivalents =no. of moles *n factor. now in your question u should know what products are being formed and also notice the change in oxidation states(that gives u the n factor) and use the relation i mentioned above
so what would you think my answer is? I'm thinking three moles of H2O
\[\large 2 Fe + 3 H_2O = Fe_{2}O_3 + 3 H_2\]
You should get 1 mole of \[Fe_2O_3\]
ok, thanks!
Try to construct the reaction and then balance it, you'll see it clearly
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