In a national chess tournament, 40% of the players are eliminated each day. If the tournament starts with 2,000 players, to the nearest integer, how many players will be present at the start of the 5th day of play?

Question

anonymous · Answer

need the equatiion

anonymous · Answer

to reduce a number by 40% multiply by $0.6$ because if you have 40% less you have 60% of what you started with

anonymous · Answer

so your job is to multiply by $.6$ 5 times in a row, more easily written as multiply by $.6^5$

anonymous · Answer

hmn. At end of day t, population is 2000*(0.6^t). At start of day five, there are the same number as at the end of day four, so 2000*(0.6^4)

anonymous · Answer

scratch that, beginning of fifth day i guess it would be $2000\times .6^4$

anonymous · Answer

1295/5 ?

anonymous · Answer

259.2

anonymous · Answer

i get this http://www.wolframalpha.com/input/?i=2000*.6^4

anonymous · Answer

yes, that looks good. nearest integer is 259