Question

2cosx+sin^2x finding critical values Finding the derivative and simplifying I have sinx=cosx, why is π a critical value. Isnt π/4(n)?

Answer 1

Is it sin square x in second term?

Answer 2

yes second term (sinx)^2

Answer 3

Then we have the first derivative as -2SinX+2SinX*CosX
Equating it to zero we have
2SinX(CosX-1)=0
From this we have
SinX=0 or X=npie
& CosX=1 or x=2npie
Hence Pie is obviously a critical value.

I suggest you to check your first derivative.

Answer 4

thanks