Find the complex zeros of f(x) = x^6 + x^5+ x^4 + 4x^3 – 12x^2 + 12
i think it's 6, 4, 2 or 0
hmm...can you make sure there isnt a term missing? inbetween the -12x^2 and 12? otherwise, this is not something that could be done by hand most likely. You would need either a calculator or computer.
there's no term missing, in between the -12x^2 and 12 is +
hm...well, none of those numbers you posted are zeros. If you want to check if a number is a zero of a polynomial, plug in the number and make sure you get 0 for an answer. For example, if I thought 0 was a zero of the polynomial, I would compute:\[0^6+0^5+0^4+4\cdot0^3-12\cdot 0^2+12\]which gives me an answer of 12. Not 0. Likewise, if you plug in any of the other numbers you guessed, none of them would work either.
hmm.. try the descartes' rule of signs
im not quite sure though, just checking my answer, and my answer is the possible complex zeros are 6, 4, 2 or 0
oh, was the question, "what are the possible roots?" or "what are the roots?"
possible roots, yeah sorry i forgot to type that in
lol <.< thats totally different then. Yes you are correct. You forgot 1 and 12 though. and take off 0. You have to use the Rational Roots Theorem.
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