Question

Suppose a particular jet needs to attain a speed of 220 mph to take off. If it can accelerate from 0 to 220 mph in 45 seconds, how long must the runway be? Assume constant acceleration. Note: 1 mph = 22/15 ft/sec.
(answer in feet)

Answer 1

@Ldaniel are you here

Answer 2

is 7260ft the right answer?

Answer 3

The answer should be 7260 feet.

Reason:
s=ut+1/2*a*t^2

u=initial vel=0
s= distance
a= acceleration
t= time taken

Therefore
a= (v-u) / t = (220-0) /45 = 220/45

s= 0+ (1/2) * (220/45)*(45)^2

Simplifying, you get
s= 4950 miles

Converting into feet by multiplying by 22/15 ft/sec

You will get
s=7260 feet

@Siddharth18 , you are right :)

Answer 4

yes i agry with him