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Find constants a and b so that the minimum for the parabola f(x)=x^2+ax+b is at the point (6,7)
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I thought the derivative equals 2x+a
?
I did it right in the last equation.
\[f'(x)= 2 x +a\\ f(6) = 6^2 + 6 a + b =7\\ f'(6)= 2(6) + a =0\\ \] You find a =12 and b=43
ok ill try it thank u
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it says b was 43 but a wasnt twelve. Do you know what could have been wrong?
??
a=-12 b=43
ughh thanks hah ah i posted a new one very similar cuz it made me start with new values
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